Question

If cosA=12/13, then find Sina and tanA

Answer 1

Hi ,

Cos A = 12 /13 ----( 1 )

We know the Trigonometric identity

Sin²A + cos² A = 1

Sin² A + ( 12 /13 )² = 1

Sin² A + 144 / 169 = 1

Sin² A = 1 - ( 144 / 169 )

Sin² A = ( 169 - 144 ) / 169

Sin² A = 25 / 169

Sin A = √( 5/ 13 )²

Sin A = 5 / 13 --- ( 2 )


Tan A = sinA / cosA

= ( 5/13 ) / ( 12 / 13 )

= 5/12

Therefore ,

SinA = 5/13,

TanA = 5/12

I hope this helps you.

:)

Answer 2

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