If cosA=12/13 then find the value of 2sinA-TanA divided by tanA+2sinA
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Answer:
Step-by-step explanation:
Given that cosA = 12/13
=>cosA = b/h = 12/13
Then, p = √(h²-b²)
= √{(13)²-(12)²}
= √(169-144)
= √25
= 5
Now, sinA = 5/13 and tanA = 5/12
So, (2sinA-tanA)/(tanA+2sinA)
= (2×5/13-5/12)/(5/12+2×5/13)
= (10/13-5/12)/(5/12+10/13)
= {(120-65)/156}/{(65+120)/156}
= (55/156)/(185/156)
= 55/185
= 11/37
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