If cosA=12/13, then verify that sinA(1- tanA) = 35/156
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cosA = 12/13 = b/h
⇒b = 12 and h = 13
from Pythagoras theorem,
hypotenuse² = perpendicular ² + base²
[here, p = perpendicular, h =hypotenuse, b = base ]
p² = h² - b² = 13² - 12² = 169 - 144 = 25
⇒p = 5
now, sinA = p/h = 5/13
and tanA = p/b = 5/12
LHS = sinA(1 - tanA)
= 5/13 × (1 - 5/12)
= 5/13 × (12 - 5)/12
= 5/13 × 7/12
= (5 × 7)/(13 × 12)
= 35/156 = RHS
hence, LHS = RHS
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3
Answer:
35/156 RHS
Step-by-step explanation:
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