Question

if cosA =12/13find sinA ,tanA​

Answer 1

Step-by-step explanation:

$sin \alpha = \sqrt{1 - {cos}^{2} } \alpha \\ = \sqrt{1 - { \frac{12}{13} }^{2} } \\ = \sqrt{1 - \frac{144}{169} } \\ = \sqrt{ \frac{169 - 144}{169} } \\ = \sqrt{ \frac{25}{169} } \\ = \frac{5}{13 } \\ \\ \tan( \alpha ) = \frac{ \sin( \alpha ) }{ \cos( \alpha ) } \\ = \frac{ \frac{5}{13} }{ \frac{12}{13} } \\ = \frac{5}{12}$