Question

If cosA=12/13then find sin A and tan A

Answer 1

Answer:

SinA=5/13 and TanA=5/12

Step-by-step explanation:

CosA=12/13 which is equal to base/hypotenuse

hypotenuse =13 and base =12

So by pythagoras theorem

H^2=P^2+B^2

13^2=P^2+12^2

169=P^2+144

169-144=P^2

25=P^2

therefore, 5=Perpendicular

Now

SinA=perpendicular/hypotenuse

=5/13

TanA=perpendicular/base

=5/12

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HOPE IT HELPS