Question

if cosA=2/3 then 2 sec2A + 2 t an2A -7
a) 3
b) 2
c) 1
d) 0​

Answer 1

Answer:

0

Step-by-step explanation:

cosA = 2/3 = Base/Hypotenuse

Base = 2, Hypotenuse = 3

Using Pythagoras theorem

Hypotenuse² = Perpendicular ² + Base²

Perpendicular = √(3² - 2²) = √(9 - 4) = √5

secA = 1/cosA = 3/2

tanA = Perpendicular/Base = √5/2

2sec²A + 2tan²A - 7 = 2*(3/2)² + 2*(√5/2)² - 7

= 9/2 + 5/2 - 7 = (9 + 5 - 14)/2 = 0