if cosA=2/5 find the value of 4+4tan2A
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Answered by
43
here,
cosA =2/5
now,we know that
tan2A = (1-cos²A) / (1+cos²A)
now 4+4tan2A =4 +4*{1-(2/5)²} / {1+(2/5)²}
=> 4+4{1- 4/25} / {1+4/25}
=> 4+4(25-4) / (25+4)
=> 4+84/29=(116 + 84) / 29 =200 /29 =6.89 answer
hope it helps ........
cosA =2/5
now,we know that
tan2A = (1-cos²A) / (1+cos²A)
now 4+4tan2A =4 +4*{1-(2/5)²} / {1+(2/5)²}
=> 4+4{1- 4/25} / {1+4/25}
=> 4+4(25-4) / (25+4)
=> 4+84/29=(116 + 84) / 29 =200 /29 =6.89 answer
hope it helps ........
Ashish447theSpecial:
Plzzz explain it breafly ..
Answered by
38
hope this will help u
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