If cosA =3/5.Find cot^2A -1
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agni3:
Sir it's cosA =3/5 and it's not cotA
ooov extremly sorry
No problem
thankuuu but really yr its...... sit
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Trigonometry,
We have,
cosA = 3/5
Have to find cot²A - 1
Now,
sin²A + cos²A = 1
or, sin²A = 1 - cos²A
or, sin²A = 1 - 9/25
or, sin²A = 16/25
or, sinA = 4/5
As we know that ,
cotA = cosA/sinA
= (3/5)/(4/5)
= 3/4
So cot²A - 1
= 9/16 - 1
= (9 - 16)/16
= -7/16
That's it
Hope it helped (^_^メ)
We have,
cosA = 3/5
Have to find cot²A - 1
Now,
sin²A + cos²A = 1
or, sin²A = 1 - cos²A
or, sin²A = 1 - 9/25
or, sin²A = 16/25
or, sinA = 4/5
As we know that ,
cotA = cosA/sinA
= (3/5)/(4/5)
= 3/4
So cot²A - 1
= 9/16 - 1
= (9 - 16)/16
= -7/16
That's it
Hope it helped (^_^メ)
Thank you so much
my pleasure
Sir isn't it 9cot^2
I am not able to get to your point
what are you saying
and there is no sir
most of brainly members are students and so as I.So don't need to call sir
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