If cosA =3/5.Find cot^2A -1
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hope its help u dear
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agni3:
Sir it's cosA =3/5 and it's not cotA
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Trigonometry,
We have,
cosA = 3/5
Have to find cot²A - 1
Now,
sin²A + cos²A = 1
or, sin²A = 1 - cos²A
or, sin²A = 1 - 9/25
or, sin²A = 16/25
or, sinA = 4/5
As we know that ,
cotA = cosA/sinA
= (3/5)/(4/5)
= 3/4
So cot²A - 1
= 9/16 - 1
= (9 - 16)/16
= -7/16
That's it
Hope it helped (^_^メ)
We have,
cosA = 3/5
Have to find cot²A - 1
Now,
sin²A + cos²A = 1
or, sin²A = 1 - cos²A
or, sin²A = 1 - 9/25
or, sin²A = 16/25
or, sinA = 4/5
As we know that ,
cotA = cosA/sinA
= (3/5)/(4/5)
= 3/4
So cot²A - 1
= 9/16 - 1
= (9 - 16)/16
= -7/16
That's it
Hope it helped (^_^メ)
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