Question

if cosA=3/5 then find the value of sin square A-cos square A
​

Answer 1

cosA=3/5= b/h

so,

p=√(5)2 √(3)2

=√25-√9

=√6= 4

Now, According to question...

sinA-cosA/2tanA

=4/5-3/5 /2* 4/3

= 4-3/5 /8/3=1/5* 3/8

=3/40

Answer 2

Answer:

We know, sin2A=2sinAcosA

⇒sin2A=2

1−

4

3

×

2

3

=2×

2

1

×

2

3

=

2

3