If cosA =3/5 then sinA/cosecA will be...................
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Aɴsᴡᴇʀ :-
ᴄᴏs = ʙᴀsᴇ / ʜʏᴘᴏᴛᴇɴᴜsᴇ = 3/5
sᴏ,
ʙᴀsᴇ = 3
ʜʏᴘᴏᴛᴇɴᴜsᴇ = 5
ᴘᴇʀᴘᴇɴᴅɪᴄᴜʟᴀʀ = √ (5)² - (3)² => √ 25 - 9 => √ 16 = 4
sɪɴA= ᴘᴇʀᴘᴇɴᴅɪᴄᴜʟᴀʀ/ʜʏᴘᴏᴛᴇɴᴜsᴇ = 4/5
ᴄᴏsᴇᴄA= ʜʏᴘᴏᴛᴇɴᴜsᴇ/ᴘᴇʀᴘᴇɴᴅɪᴄᴜʟᴀʀ=5/4
Tʜᴇʀᴇғᴏʀᴇ,
sɪɴA / ᴄᴏsᴇᴄA
= = > 4/5/5/4
= = > 16/25
Hᴏᴘᴇ ɪᴛ ʜᴇʟᴘs..!
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