Math, asked by kuppalaramesh, 3 months ago

If cosA=3/5,then write the value of sinA​

Answers

Answered by pankajgupta985244248
0

Answer:

sinA=4/5

Step-by-step explanation:

cosA=B/H=3/5

B=3x, H=5x

p =  \sqrt{ {5x}^{2} -  {3x}^{2}  }

p=4x

sinA=P/H=4x/5x

sinA=4/5

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