Question

If cosA=3/5find the value of sinA -1/tanA/2tanA

Answer 1

cos A = 3/5

cos A = base/hypotenuse

Base = 3

Hypotenuse = 5

Perpendicular^2 = 5^2 - 3^2

Perpendicular = √16

= 4

sin A - 1/tan A/2tan A

= 4/5 - 1/(4/3)/2(4/3)

= 4/5 - 2

= -6/5