Question

if cosA=4/5, find sinA and cosA.​

Answer 1

Step-by-step explanation:

${ \sf{ \underline{ \red{ \underline{ \red{Given}}}} : -}}$

$\displaystyle \sf \longrightarrow \: \cos(a) = \frac{4}{5}$

${ \sf{ \underline{ \red{ \underline{ \red{To Find}}}} : -}}$

$\displaystyle \sf \longrightarrow \: \sin(a) \: and \: \cos(a)$

${ \sf{ \underline{ \red{ \underline{ \red{Solution}}}} : -}}$

$\displaystyle \sf \tt \ : \implies \cos(a) = \: \frac{4}{5} \\ \\ \displaystyle \sf \tt \ : \implies \frac{b}{h} = \frac{4}{5} \: \: \: \: \: \: \: \: \: \\ \\ \displaystyle \sf \bigstar \: \: \: \: b \: = 4 \: and \: h \: = \: 5 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \displaystyle \sf \bigstar \: \: \: \: p \: = \: 3(for \: triplates) \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \displaystyle \sf \tt \ : \implies \sin(a) = \frac{p}{h} = \frac{3}{5} \\ \\ \displaystyle \sf \tt \ : \implies \tan(a) = \frac{p}{b} = \frac{3}{4}$