Question

if cosA= .53 and perpendicular is 20m then what is the base​

Answer 1

Step-by-step explanation:

By pythagoras theorem :-

H2 = B2 + (20)^2

H2 = B2 + 400

H = √B^2 + 400

Cos A = Base ÷ Hypotenuse

53 = B / (√B^2 + 400)

On squaring both sides

(53)^2 = B^2 / (B^2 + 400)

2809 = B^2 / (B^2 + 400 )

On Cross Multipication