Question

If CosA=6/10, find the values of tanA and SinA.​

Answer 1

Answer:

$\cos(a) = \frac{6}{10} \\ we \: know \: , \: \cos(x) = \frac{b}{h} \\ here, \: b = 6, \: h = 10 \\ {h}^{2} = {p}^{2} + {b}^{2} \\ = > {p}^{2} = {h}^{2} - {b}^{2} \\ = > {p}^{2} = {10}^{2} - {6 }^{2} \\ = > {p}^{2} = 100 - 36 \\ = > {p}^{2} = 64 \\ = > p = \sqrt{64} \\ = > p = 8 \\ then, \: \tan(a) = \frac{p}{b} = \frac{8}{6} = \frac{4}{3} \\ and \: \sin(a) = \frac{p}{h} = \frac{8}{10} = \frac{4}{5}$

Answer 2

Step-by-step explanation:

We know,

sin²A + cos²A = 1

put cosA value in above's equation ;

sin²A +(6/10)² = 1

sin²A +(36/100) = 1

sin²A = 1 - (36/100)

sin²A = 64/100

sinA = 8/10

now,

tanA = sinA/cosA

tanA = (8/10)/(6/10)

tanA = 8/6

tanA = 4/3