if cosA =7/25 then find tanA+cotA
Answers
Answered by
3
cos A = adjacent/hypotenuse
adj=7
hypo=25
so applying Pythagoras theorem
we get opp=24
now tanA=opp/adj
=24/7
cotA=7/24
adding both we get
625/168
here's Ur answer
hope it helps
adj=7
hypo=25
so applying Pythagoras theorem
we get opp=24
now tanA=opp/adj
=24/7
cotA=7/24
adding both we get
625/168
here's Ur answer
hope it helps
Answered by
4
Heya Mate!!!
CosA= Base/Hypotenuse = 7/25
perpendicular = ?
By Using Pythagorean Theorem..
H² = P² + B²
25² = P² + 7²
P² = 25² - 7²
P² = 625 - 49
P² = 576
(P)² = (24)²
SQUARE CANCELLED BOTH SIDE...
WE GET
P = 24
NOW , WE HAVE
P = 24
H = 25
B = 7
TanA = P/B
= 24/7
CotA = B/P
= 7/24
Then putting these value in...
tanA + CotA
= (24/7) + ( 7/24)
= (24 × 7 + 7 × 24)/168
= (168 + 168)/168
= ( 336)/168
= 2
Hope you like it....❤❤
CosA= Base/Hypotenuse = 7/25
perpendicular = ?
By Using Pythagorean Theorem..
H² = P² + B²
25² = P² + 7²
P² = 25² - 7²
P² = 625 - 49
P² = 576
(P)² = (24)²
SQUARE CANCELLED BOTH SIDE...
WE GET
P = 24
NOW , WE HAVE
P = 24
H = 25
B = 7
TanA = P/B
= 24/7
CotA = B/P
= 7/24
Then putting these value in...
tanA + CotA
= (24/7) + ( 7/24)
= (24 × 7 + 7 × 24)/168
= (168 + 168)/168
= ( 336)/168
= 2
Hope you like it....❤❤
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