if cosA=9/41;find the value of :1/sin²A-cot²A
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Answered by
3
Answer:
1600/1519
Step-by-step explanation:
cosA=9/41
cosA=Base/ Hypotenous
According to Phythogoreous Theorem..
H² = P² + B²
P² = H²- B²
P² = (41)²-(9)²
P² = 1681-81
P² = 1600
P = _/1600
P = 40
sinA = P/H= 40/41
sin²A= 1600/1681
cos²A= 81/1681
1/(sin²A-cot²A)
1/(sin²A- cos²A)/sin²A
= sin²A/(sin²A-cos²A)
= (1600/1681 )/(1600-81)/1681
= 1600/1519 Ans ..
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2
Hi friend here is your answer...
Given : ![cosA=\frac{9}{41} \\Then sinA will be \frac{40}{41}\\We\: have\: to\: find\:= \frac{1}{sin^{2} -cot^{2} }\\apply\: the\: values\:in\: above\:eqaution cosA=\frac{9}{41} \\Then sinA will be \frac{40}{41}\\We\: have\: to\: find\:= \frac{1}{sin^{2} -cot^{2} }\\apply\: the\: values\:in\: above\:eqaution](https://tex.z-dn.net/?f=cosA%3D%5Cfrac%7B9%7D%7B41%7D+%5C%5CThen+++++sinA+++++will++++be+++++%5Cfrac%7B40%7D%7B41%7D%5C%5CWe%5C%3A+have%5C%3A+to%5C%3A+find%5C%3A%3D+%5Cfrac%7B1%7D%7Bsin%5E%7B2%7D+-cot%5E%7B2%7D+%7D%5C%5Capply%5C%3A+the%5C%3A+values%5C%3Ain%5C%3A+above%5C%3Aeqaution)
Hope my answer will help you..
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