Question

if cosA is -12/13 then sin A is​

Answer 1

Answer:

solution, cosA=-12/13=b/h,p=?

p^2=h^2-b^2

p^2=13^2-12^2

p^2=169-144

p^2=25

p=5

sinA=p/h=5/13

Answer 2

Answer:

5/3

Step-by-step explanation:

we know ,

sin^2A+cos^2A=1

=>sin^2A=1-cos^2A

=>sin^2A=1-(-12/13)^2

=1-(144/169)

=25/169

=(5/13)^2

so we get,

sin^2A=(5/13)^2

by taking root over both side,

sinA=5/13 (Ans.)