Question

If cosA+secA=2 , then find the value of cos^2A+sec^2A .

Answer 1

Answer:

2

Step-by-step explanation:

Given, cosA + secA = 2

now, using (a + b)² = a² + b² + 2ab

(cosA + secA)² = cos²A + sec²A + 2(cosA)(secA)          

(2)² = cos²A + sec²A + 2(1)

4 = cos²A + sec²A + 2

cos²A + sec²A = 4-2

cos²A + sec²A = 2

(cosA x secA= i/secA x sexA = 1)        

Hope this was helpful!!! :)