If cosA + sinA = √2 sin(90-A), then find the value of cotASolve this
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cosA +sinA=√2cosA
cosA+sinA=√2cos(90-A)
cosA+sinA=√2sinA
1/sinA(cosA+sinA)=√2
cosA/sinA+sinA/sinA=√2. {cosA/sinA=cotA}
cotA+1=√2
cotA=√2-1
cosA+sinA=√2cos(90-A)
cosA+sinA=√2sinA
1/sinA(cosA+sinA)=√2
cosA/sinA+sinA/sinA=√2. {cosA/sinA=cotA}
cotA+1=√2
cotA=√2-1
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