if cosA+sinA =√2cosA then show dat cosA-sinA = √2sinA pls I need proper answer
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hello....
cosA + sinA=√2cos A
squaring both side.
(cosA+sinA)^2 =(√2cosA)^2
cosA^2 + sinA^2 + 2cosAsinA= 2cos^2
sin^2= cosA^2-2cosAsinA. {cosA^2=1-sinA^2}
sinA^2 = 1-sinA^2-2 cosAsinA
2sin^2= 1-2cosAsinA
2sinA^2= cisA^2-sinA^2. { cosA^2 +sinA^2 =1}
√2sinA= cosA-sinA
Hence proved..
I hope it help you.....
please mark it as a brainieist answer.......
cosA + sinA=√2cos A
squaring both side.
(cosA+sinA)^2 =(√2cosA)^2
cosA^2 + sinA^2 + 2cosAsinA= 2cos^2
sin^2= cosA^2-2cosAsinA. {cosA^2=1-sinA^2}
sinA^2 = 1-sinA^2-2 cosAsinA
2sin^2= 1-2cosAsinA
2sinA^2= cisA^2-sinA^2. { cosA^2 +sinA^2 =1}
√2sinA= cosA-sinA
Hence proved..
I hope it help you.....
please mark it as a brainieist answer.......
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