If cosA-sinA=√2sinA prove cos A +sinA=√2cos A who give me answer first I will add him in a brainleist
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cos A - sin A = √2 sin A
[ squaring both sides ]
(cos A - sin A)² = ( √2 sin A )²
cos²A + sin²A - 2. cos A. sin A = (√2)². sin²A
cos²A + sin²A - 2. cos A. sin A = 2 sin²A
cos²A - 2. cos A. sin A = 2 sin²A - sin²A
cos²A - 2. cos A. sin A = sin²A
cos²A = sin²A + 2. cos A. sin A
[ adding cos²A on both sides ]
cos²A + cos²A = sin²A + 2.sin A. cos A + cos²A
2 cos²A = (sin A + cos A)²
[ shift sq to left side ]
√2. √cos²A = sin A + cos A
√2 cos A = sin A + cos A
[ arrange ]
sin A + cos A = √2 cos A
Hence proved
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hope my answer helps u.......... :D
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cos A - sin A = √2 sin A
[ squaring both sides ]
(cos A - sin A)² = ( √2 sin A )²
cos²A + sin²A - 2. cos A. sin A = (√2)². sin²A
cos²A + sin²A - 2. cos A. sin A = 2 sin²A
cos²A - 2. cos A. sin A = 2 sin²A - sin²A
cos²A - 2. cos A. sin A = sin²A
cos²A = sin²A + 2. cos A. sin A
[ adding cos²A on both sides ]
cos²A + cos²A = sin²A + 2.sin A. cos A + cos²A
2 cos²A = (sin A + cos A)²
[ shift sq to left side ]
√2. √cos²A = sin A + cos A
√2 cos A = sin A + cos A
[ arrange ]
sin A + cos A = √2 cos A
Hence proved
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hope my answer helps u.......... :D
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