Math, asked by dpadeekhan, 1 year ago

If cosa - sina= √2sina,then prove that cosa + sina= √2cosa

Answers

Answered by Sakshi15403
69
hope it will help you....
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Answered by SerenaBochenek
40

Answer:

Proved is given below.

Step-by-step explanation:

Given that cos a - sin a =\sqrt2 sina

we have to prove cos a + sin a =\sqrt 2 cos a

cos a - sin a =\sqrt2 sina\\\\cosa=\sqrt2sina+sina\\\\sina=\frac{coaa}{\sqrt2+1}

By rationalizing, we get

sina=\frac{cosa}{\sqrt2+1}\times\frac{\sqrt2-1}{\sqrt2-1}=\frac{(\sqrt2-1)cosa}{(\sqrt2)^2-1^2}=(\sqrt2-1)cosa

sina=\sqrt2cosa-cosa

sina+cosa=\sqrt2cosa

Hence proved.

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