Math, asked by ghanshyamtrivedi19, 11 months ago

If cosA-sinA/cosA+sinA=1-root3/1+root3. Find A? Please tell...

Answers

Answered by vaishnavirsomanii
9

Answer:(::) hope it helps (::)...please mark as brainliest

Step-by-step explanation:

(cosA+sinA)/(cosA-sinA) = (1 +√3) / (1- √3)

we have to find 

A = ? 

solution :-

here ,

(cosA+sinA)/(cosA-sinA)

= cos A ( 1 + tan A) / cos A ( 1 - tan A) 

= (1 + tan A ) / ( 1- tan A ) 

now ,

(1 +√3) / (1- √3) 

= (1 + tan 60° ) / ( 1- tan 60° )       

because tan 60° = √3

now,

 by comparing

 (1 + tan A ) / ( 1- tan A ) and (1 + tan 60° ) / ( 1- tan 60° ) 

=> tan A = tan 60°

=> A = 60° answer 


ghanshyamtrivedi19: How?cosA+sinA)/(cosA-sinA)

= cos A ( 1 + tan A) / cos A ( 1 - tan A)

Plz tell
vaishnavirsomanii: if we take cos A as common out of(cos A+ sin A)
it will be cosA (1 + tan A) bcoz cos A x tan A = sin A
similarly for the second bracket
vaishnavirsomanii: if u understand then please mark as brainliest
Answered by brunoconti
3

Answer:

Step-by-step explanation:

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