If cosA-sinA/cosA+sinA=1-root3/1+root3. Find A? Please tell...
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Step-by-step explanation:
(cosA+sinA)/(cosA-sinA) = (1 +√3) / (1- √3)
we have to find
A = ?
solution :-
here ,
(cosA+sinA)/(cosA-sinA)
= cos A ( 1 + tan A) / cos A ( 1 - tan A)
= (1 + tan A ) / ( 1- tan A )
now ,
(1 +√3) / (1- √3)
= (1 + tan 60° ) / ( 1- tan 60° )
because tan 60° = √3
now,
by comparing
(1 + tan A ) / ( 1- tan A ) and (1 + tan 60° ) / ( 1- tan 60° )
=> tan A = tan 60°
=> A = 60° answer
if we take cos A as common out of(cos A+ sin A)
it will be cosA (1 + tan A) bcoz cos A x tan A = sin A
similarly for the second bracket
it will be cosA (1 + tan A) bcoz cos A x tan A = sin A
similarly for the second bracket
if u understand then please mark as brainliest
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= cos A ( 1 + tan A) / cos A ( 1 - tan A)
Plz tell