Question

if cosA -sinA=under square root 2 then prove that cosA - sinA =under sq.root 2?......100 points for that but the ans should be proper

Answer 1

Hey mate ^_^

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Answer:
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CosA +sinA = √2cosA

Squaring,

⇒(cosA + sin A)² = (√2cosA)²

⇒cos²A + sin²A + 2sinAcosA = 2cos²A

⇒1 - sin²A + 1 - cos²A + 2sinAcosA = 2cos²A

⇒2 - 2cos²A = cos²A + sin²A - 2sinAcosA 

⇒2(1 - cos²A) = (cosA - sinA)²

⇒ cosA - sinA = √[2sin²A]

⇒cosA-sinA = √2sinA

Hence proved.

#Be Brainly❤️

Answer 2

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