Question

If cosA = $\frac{2a}{\sqrt{a^{2} +1} }$ . Find sinA and tanA

Answer 1

Step-by-step explanation:

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Answer 2

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cos A = 2a /sqrt(a^2 +1)

cos^2A %= 4a^2/ a^2+1

sin^2A = 1 - 4a^2/1+ a^2

sinA = sqrt {(1 - 4a^2)/(1+a^2)}

tanA = sinA/cosA = sqrt(1-4a^2)/2a

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