if cosA2/3 then find 4+4tan squareA
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cosa=2/3
therefore sina=√1-cos^2a
sina=√1-(2/3)^2=√1-4/9=√5/3
sina=√5/3
tana=(√5/3)/(2/3)=√5/2
tan square a=5/4
4+4tan^2a =4+4(5/4)=9
therefore sina=√1-cos^2a
sina=√1-(2/3)^2=√1-4/9=√5/3
sina=√5/3
tana=(√5/3)/(2/3)=√5/2
tan square a=5/4
4+4tan^2a =4+4(5/4)=9
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