Question

If (cosalpha,sinalpha,0),(cosbeta,sinbeta,0),cosgama,singama,0) are the vertices of the triangle then circum radius R is

Answer 1

Circum Radius  = 1 , circum center would be (0 , 0 , 0)

Step-by-step explanation:

(cosalpha,sinalpha,0),(cosbeta,sinbeta,0),cosgama,singama,0) are the vertices of the triangle

z coordinates is same for all  so we can ignore that

(cosα,sinα),(cosβ,sinβ),(cosγ,sinγ)  are (x , y) cordinates of vertices of triangle

just by looking  we can conclude that

cos²α + sin²α  = 1

cos²β + sin²β  = 1

cos²γ + sin²γ  = 1

we can say that all points lies on a circle  which have radius = 1

& center (0 , 0)

So circum center would be (0 , 0 , 0)

Circum Radius  = 1

Learn more:

Find the co-ordinates of the circumcentre of the triangle formed by ...

https://brainly.in/question/12127230

then circumcentre of triangle is

https://brainly.in/question/2309436

Answer 2

ans:1 step by step:-.

it is of the form x^2+y^2=r^2

in which it represents a equation of circles

that is circumradius is equals to 1