if cosb -sinb=√2 sinb then cosb+ sinb
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Answered by
1
Answer:
0
Step-by-step explanation:
For simplicity, let cosB = a and sinB = b.
As sin²B + cos²B = 1, a² + b² = 1.
Square on both sides 'cosB - sinB = √2':
=> (a - b)² = (√2)²
=> a² + b²- 2ab = 2
=> 1 - 2ab = 2
=> 2ab = - 1
Therefore, (a + b)²
= a² + b² + 2ab
= 1 + (-1)
= 0, thus a + b = 0
Hence, cosB + sinB = a + b = 0
Answered by
3
Answer:
your answer is 0✍️✍️
hope it is help you✔️✍️
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