Question

If cose A = 7÷4 prove that 1+tan2A=sec2A

Answer 1

Answer:

Cosec A = 7/4 => hypotenuse = 7x and perpendicular = 4x

ACC TO PYTHAGORAS THM, base^2 = 49 x^2 - 16x^2 = 33x ^2

now 1+ tan^2A = 1 + 16/33 = 49 /33

SEC^2A=HYPOTENUSE^2/BASE^2

               =49/33=LHS

PROVED

Step-by-step explanation: