Question

If cose + cos²o = 1, find the value of 12 2 sin 20 + 6 Sin" 0 + 6 sin ³0 + 2 sin³0 - 1​

Answer 1

Answer:

Given,

 sinA=1312

We know that,

sinA=HypotenuseoppositeSide

From Pythagoras theorem,

 (Hypotenuse)2=(oppositeSide)2+(adjacentSide)2

132=122+(adjacentSide)2

(adjacentSide)2=169−144=25

(adjacentSide)=5

cosA=HypotenuseAdjacentSide=135

tanA=AdjacentSideOppositeSide=512

Therefore,

2sinθcosθsin2θ−cos2θ×tan2θ1

==2(1312)(135)(1312)2−(135)2×(512)21

=2(1312)(135)(169144)−(16925)×14425

=(169120)(169144−25)×14425

=120119×14425

Step-by-step explanation:

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