Question

If cosec 0- cot 0 = q, then the value of cosec 0 is

Answer 1

Answer:

$your \: answer \: is \\ \frac{ {q}^{2} + 1 }{2q}$

Step-by-step explanation:

${cosec}^{2} 0 - {cot}^{2} 0 = 1 \\ (cosec \: 0 - cot \: 0)(cosec \: 0 + cot \: 0) = 1 \\ q(cosec \: 0 + cot \: 0) = 1 \\ cosec \: 0 + cot \: 0 = \frac{1}{q} \\ \\ now \: \\ \csc(0) + \cot(0) = \frac{1}{q} \\ \csc(0) - \cot(0) = q \\ adding \\ 2 \csc(0) = q + \frac{1}{q} \\ 2 \csc(0) = \frac{ {q}^{2} + 1}{q} \\ \csc(0) = \frac{ {q}^{2} + 1}{2q}$