If cosecθ = √10, then find the values of other t–ratios of angle θ.
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Step-by-step explanation:
We know that,
cosecθ = Hypotenuse / Opposite side to theta
cosecθ = √10 / 1
Hypotenuse = √10
Opposite side = 1
By Pythagoras theorem,
( Hypotenuse )² = (Adjacent side) ²+ (Opposite side) ²
Adjacent side = √[ ( √10)² - 1² ] = √9 = 3
Now, Trigonometry ratios :
cosθ = Adjacent side to theta / Hypotenuse = 3/√10
sinθ = Opposite side of theta / Hypotenuse = 1/√10
tanθ = sinθ/cosθ = 1/3
cotθ = 1/tanθ = 1/( 1/3) = 3
secθ = 1/cosθ = 1/(3/√10) = √10/3
∴ The trigonometric ratios , cosθ = 3/√10 , sinθ = 1/√10 , tanθ = 1/3 , cotθ = 3 , secθ = √10/3
Hope it will help you
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