Question

if cosec = 13/12 , evaluate 2sin-3cos/4sin-9cos​

Answer 1

Answer:

Step-by-step explanation:

cosec theta = 13/12

sin theta = 12 /13---(1)

cos theta = √1-sin² theta

= √1- (12/13)²

= √1- 144/169

= √(169-144)/169

=√25/169

= 5/13

therefore sin theta = 12/13, cos theta =5/13

(2sin theta -3 cos theta) /(4sin theta -9 cos theta)

= (2*12/13 - 3*5/13) /(4*12/13 - 9* 5/13)

=( 24/13 - 15/13)/ (48/13 - 45/13)

= [(24-15)/13]/[(48-45)/13]

=9/3

=3