If cosec=13/12 theb find the value of 2sin-3cos/4sin-9cos
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Answered by
0
Answer:
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Answered by
0
Answer:
cscA(1+cosA)(cscA−cotA)=1
LHS:
sinA
1
[1+cosA][
sinA
1
−
sinA
cosA
][∵cscA=
sinA
1
,cotA=
sin
A
cos
A
]
=
sinA
A
(1+cosA)
sinA
(1−cosA)
=
sin
2
A
1−cos
2
A
[∵ cos
2
A+sin
2
A=1 sin
2
A=1−cos
2
A]
=
sin
2
A
sin
2
A
=1=RHS
Step-by-step explanation:
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