if cosec∅=2/√3, then find the value of sin²∅.cos∅+ten²∅
Answers
Answered by
2
Answer:
cosecØ=2/√3
Ø=60°
sin²ØcosØ+tan²Ø
=sin²60cos60+tan²60
=(√3/2)1/2+3
=√3/4+3
=(√3+12)/4
Similar questions