If cosec^2(3x-2)=cot^2(2x+3)+1 than x=?
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x = coseca/3
1/x = cota/3
(x²-1/x²) = (x+1/x)(x-1/x)
= (coseca/3 + cota/3)(coseca/3 - cota/3)
= 1/9 (coseca+ cota)(coseca - cota)
= 1/9 (cosec²a - cot²a)
= 1/9 (cot²a +1 - cot²a)
= 1/9 (1)
= 1/9
I hope you understand the approach.
All the best!
hitanshu30:
I didn't understand
From where does 'a' came?
just i was putting to make clear
from where does coseca/3 came
formula
I still didn't understand
which formula??
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