If cosec θ = 2, then the value of 1/tanθ +sinθ/(1+cosθ )
(a) √3/2
(b) 2
(c) 1/2
(d) √3
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cosecA =2
sinA = 1/2 this will be equation 1
cosA = √(1-sin²A)
√(1 - 1/4)
√(3/4)
√3/2 This will be equation 2
tanA = 1/2 / √3/2
= (1/2) * (2/√3)
= 1/√3 this will be equation 3
1/tanA + sinA/(1+cosA)
Now from 1 2 and 3 equations we will put the values
= 1/(1/√3) + (1/2) / ( 1+ √3/2)
= √3 + (1/2) / {(2+√3)/2}
= √3 + 1/(2+√3)
= (2√3 + 3 + 1) / (2+√3)
= 2( √3+2) / (√3+2)
= 2
The final answer is option b: 2
If there is any confusion please leave a comment below.
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