If cosec^2a(1+cosa) (1-cosa)=x then the value of x is
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Answered by
3
Hi dear
we will solve the LHS and what will be the answer we got to found will be equal to x
cosec²A(1 + cosA) ( 1 - cosA) = LHS
= 1/sin²A ( 1 -cos²A) [ ∵cosec²A = 1/sin²A ] and [ using a² - b² = (a+b) (a-b) ]
= 1/sin²A . sin²A [ 1 - cos²A = sin²A .]
= 1
value of x is 1
we will solve the LHS and what will be the answer we got to found will be equal to x
cosec²A(1 + cosA) ( 1 - cosA) = LHS
= 1/sin²A ( 1 -cos²A) [ ∵cosec²A = 1/sin²A ] and [ using a² - b² = (a+b) (a-b) ]
= 1/sin²A . sin²A [ 1 - cos²A = sin²A .]
= 1
value of x is 1
Thnx Daniel
And mystic
And mystic
Answered by
3
Hi ,
***************
we know that
1 ) 1 - cos² A = sin² A
2 ) cosecA sinA = 1
********************
x = cosec² A ( 1 + cosA ) ( 1 - cosA )
= cosec² A ( 1 - cos² A )
= cosec² A sin² A
x = 1
I hope this helps you.
:)
***************
we know that
1 ) 1 - cos² A = sin² A
2 ) cosecA sinA = 1
********************
x = cosec² A ( 1 + cosA ) ( 1 - cosA )
= cosec² A ( 1 - cos² A )
= cosec² A sin² A
x = 1
I hope this helps you.
:)
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