Question

. If cosec 2A = Sec (A + 15°), where 2A < 90° find the value of A.​

Answer 1

Answer:

cosec 2A = sec (A + 15°)

sec (90-2A) = sec (A + 15°) (secant is cancelled)

90-2A = A+ 15

90-15 = A + 2A

75 = 3A

A = 75/3

A = 25°

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Answer 2

Therefore, the value of A = 25°  

Given:  cosec 2A = Sec (A + 15°)  where 2A < 90°

To find: The value of A

Solution:

given Cosec 2A = Sec (A + 15°)    

⇒ Cosec 2A = Cosec [90° - (A+15)]       [ ∵ Cosec (90-A) = Sec A ]    

⇒ 2A = 90° - (A+15)    

⇒ 2A = 90° - A -15

⇒ 3A = 75°  

⇒ A = 25°

Therefore, the value of A = 25°    

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