If cosecθ=4 and cotθ=√3k then find k
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Answered by
1
1+cot²A=cosec²A.
1+3k²=16.
3k²=15.
k²=5.
k=√5
1+3k²=16.
3k²=15.
k²=5.
k=√5
Answered by
2
By using above method, it can be solved by this way using identities.
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