If cosec Ꮎ =
5/4
find the value of cot
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Step-by-step explanation:
Cot = B/P n cosec = H/P
in rt triangle ABC
AB^2+ BC^2=AC^2(using pythagoras theorem )
4^2+ BC=5^2
16+BC=+25
BC^2=25-16
BC= square root 9
BC =3
Therefore cot = 3/4
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