Question

if cosec^6x-cot^6x=acot^4x+bcot^2x+c then a+b+c =

Answer 1

 cosec^6 x - cot^6x 
= (cosec^2 x)^3- (cot ^2 x)^3 
= (cosec^2 x - cot^2 x)(cosec^4 x + cosec^2 x cot ^2 x + cot^4 x) 
= (cosec^4 x + cosec^2 x cot ^2 x + cot^4 x) as (cosec^2 x - cot^2 x) = 1 
= (cot^2 x +1 )^2 + (cot^2 x+1) cot^2 x + cot^ 4x 
= cot ^4 x + 2 cot^2 x + 1 + cot^4 x + cot^2 x + cot^4 x 
= 1+ 3 cot^2 x + cot^4 x 
thus a+b+c=5

Answer 2

Step-by-step explanation:

see the attachment above