Question

If Cosec A =√10.Find sec A and Cot A

Answer 1

Hi this the answer of me

when cosec A =sq root of 10

cot A = sq root of 9

sec A = sq root of 10 / 3

cosec A= sq root 10
cosec^2A= 10
Wkt,
1+ cot^2A=cosec^2A
so, 1+ cot^2A=10
cot^2A=10-1
= sq root of 9
cotA = 3.
NEXT,
cosecA =sq root 10

1/ sinA = sq root 10
sinA = 1/ sq root 10
Wkt,
cot A= 3
cosA /sinA =3
cosA = 3 × sin A
= 3× 1/ sq root 10 cosA= 3/ sq root 10
1/ sec A= 3/ sq root 10
sec A = sq root of 10.
That's the answer.