Question

if cosec A = √10 then find the 5 trigonometry ratio of A
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Answer 1

Answer:

We have,

cosecA= PerpendicularHypotenuse=110 

So, we draw a triangle ABC, right angled at B such that

Perpendicular =BC=1 unit and, Hypotenuse =AC= 10 units.

By Pythagoras theorem, we have

AC2=AB2+BC2 

⇒(10)2=AB2+12

⇒AB2=10−1=9

⇒AB=9=3

When we consider the trigonometric ratios of ∠ A , we have

Base =AB=3, Perpendicular =BC=1, and Hypotenuse =AC= 10

∴sinA=HypotenusePerpendicular=101

cosA=Hypotenuse