Question

If Cosec A = 13/ 12, find the value of 2 Sin A− 3 Cos A/ 4 Sin A−9 Cos A

Answer 1

Answer:

cosecA= height/perpendicular= 13/12

Let the base be b

b= √h^2-p^2=√(13)^2-(12)^2=5

2sinA-3cosA/4sinA-9cosA

=(2×12/13 - 3×5/13)/(4×12/13 - 9×5/13)

=(24-15)/(48-45)

=9/3

=3