Question

if cosec A=13/12 find the value of (2 sin A-3 cos A÷4 sin A -9 cos A)​

Answer 1

Answer:

$- \frac{401}{208}$

Step-by-step explanation:

$if \: \: cosec \: a = \frac{13}{12} then \: \\ \sin(a) = \frac{12}{13} \\ \cos(a) = \frac{5}{13} \\ 2 \sin(a) - 3 \cos(a) \div 4 \sin(a) - 9 \cos(a) \\ = 2 \times \frac{12}{13} - 3 \times \frac{5}{13} \div 4 \times \frac{12}{13} - 9 \times \frac{5}{13} \\ = - \frac{401}{208}$