Question

If cosec A = 17, then find
tan A - sec A/
tan A + sec A​

Answer 1

$cosec a = 17 \\ coseca = bc \div ab \\ ab = 17 \: bc = 1 \\ by \: pythagoras \: therom \\ {ac }^{2} = {ab }^{2} + {bc }^{2} \\ {ac}^{2} = 17 + 1 \\ = 18 \\ tan \: a = ab \div bc \\ tan \: a = 17 \div 1 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: sec \: a = ac \div bc$