Question

if cosec A=√2 and cot B=1. Find sin(A+B)

Answer 1

Answer:

Cosec A = √2

⇒ A = 45

Cot B = 1

⇒ 45

Sin (A+B) = $\frac{1}{\sqrt{2} }+\frac{1}{\sqrt{2} }= \frac{2}{\sqrt{2} }$

$\frac{2}{\sqrt{2} } * \sqrt{2} = \sqrt{2$

Answer 2

If cosec A=√2
cosec A=cosec 45°
A=45°
Similarly, cot B=1
cot B=cot 45°
B=45°
So, sin(A+B) = sin(45°+45°) = sin90° = 1


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