Math, asked by prannav88, 4 months ago

If cosec A = 2, sec B = 1. Find A+B and A-B.​

Answers

Answered by Anonymous
3

Answer:

Proof : From (1), 

... sec A - sec B = csc B - csc A 

∴ (1/ cos A) - (1/ cos B) = (1/ sin B) - (1/ sin A) 

∴ ( cos B - cos A ) / ( cos A. cos B ) = ( sin A - sin B ) / ( sin A. sin B ) 

∴ rearranging the terms on two sides, 

... ( sin A / cos A )( sin B / cos B ) = ( sin A - sin B ) / ( cos B - cos B ) 

∴ ( tan A )( tan B ) = [ 2. cos (A+B)/2. sin (A-B)/2 ] / [ 2. sin ((A+B)/2. sin (A-B)/2 ] 

∴ ( tan A )( tan B ) = cot [ (A+B) / 2 ] ....Okk

Answered by prage2007
1

Answer:

answer-2

Step-by-step explanation:

A=1B=2

so, a+b and a-b

= 2+1 and 2-1

=3-1

=2

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