If cosec A = 2, sec B = 1. Find A+B and A-B.
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Answered by
3
Answer:
Proof : From (1),
... sec A - sec B = csc B - csc A
∴ (1/ cos A) - (1/ cos B) = (1/ sin B) - (1/ sin A)
∴ ( cos B - cos A ) / ( cos A. cos B ) = ( sin A - sin B ) / ( sin A. sin B )
∴ rearranging the terms on two sides,
... ( sin A / cos A )( sin B / cos B ) = ( sin A - sin B ) / ( cos B - cos B )
∴ ( tan A )( tan B ) = [ 2. cos (A+B)/2. sin (A-B)/2 ] / [ 2. sin ((A+B)/2. sin (A-B)/2 ]
∴ ( tan A )( tan B ) = cot [ (A+B) / 2 ] ....Okk
Answered by
1
Answer:
answer-2
Step-by-step explanation:
A=1B=2
so, a+b and a-b
= 2+1 and 2-1
=3-1
=2
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